This (arguably unhelpful) phrase seems to be taught across schools all over the world. What are some other phrases like this that are common ?

  • Badabinski@kbin.earth
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    3 months ago

    To the tune of “Pop Goes The Weasel”:

    x equals negative b /
    plus or minus the square root /
    of b squared minus 4 ac /
    all over 2a!

    I cannot believe that stupid fucking song is still in my head, but good God damn it worked. It’s there for all 0 times I’ll need the quadratic equation in my daily life.

          • JWBananas@lemmy.world
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            3 months ago

            I’ve been hearing the Donkey Kong song in my head for the last 6 hours. If you know how to make it stop, I’m all ears.

            • ryannathans@aussie.zone
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              3 months ago

              Things tend to linger when we don’t understand them or didn’t initially hear them well

              We reprocess them until they make sense

          • ianovic69@feddit.uk
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            3 months ago

            Interesting. If you focus on your internal dialogue, that’s really the same thing except it’s saying (or singing) something external.

            • ryannathans@aussie.zone
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              3 months ago

              Yes, I mean I have 10/10 visualisation/internal hearing/etc but the language denotation of “hearing” something that does not enter your auditory nerve is… odd

        • Bitrot@lemmy.sdf.org
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          3 months ago

          I’ve never seen it with the x equals up front. It works much better when it starts with -b.

    • JackbyDev@programming.dev
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      3 months ago

      It was to to the tune of Frère Jacques when I learned it. https://en.wikipedia.org/wiki/Frère_Jacques

      Negative b, negative b
      Plus or minus square root, plus or minus square root
      B squared minus 4 AC, b squared minus 4 AC
      Over 2A, over 2A

      Finding the name of the original song was a pain. I’d never seen it written as an adult and thought it said “do re mi” so every search result kept telling me it was from the sound of music.

    • Caveman@lemmy.world
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      3 months ago

      If you already know that much algebra you can use ax2 + bx + c = 0 and solve for x to get the formula if you forget it.

      • JWBananas@lemmy.world
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        3 months ago

        Hurr durr what if I just multiply the whole thing by 4a for some reason? Oh and then after that I’ll add b² to both sides, just for shits and giggles. And for good measure, I’ll move a few numbers from one side to the other, and that leaves me with 4a²x² + 4abx + b² = b² - 4ac.

        And then golly gee! Wouldn’t you know it? That just happens to let the left side factor neatly into (2ax + b)²! So I’ll just take the square root of both sides…

        No!

        No!

        Bad!

        This is fucking voodoo. I hate this shit. It’s like trigonometric substitution.

        Math is procedural. Math is algorithmic. Math is repeatable.

        “If these numbers looked a little different than they do, I could solve this. Oh, wow! If I just sprinkle these magic values into my problem, everything works out great!”

        Oh yes, I can see how if you just plug in this shit you pulled out of your ass, everything works out great! But when you aren’t around for a fecal transfer, I have no idea how to come up with that.

        I was top of my class in math. But that voodoo shit never made any sense to me.

        And there is absolute value of zero chance I could figure all that out in the heat of the moment if I forgot the quadratic formula. I had to work backwards from the formula to even get all that in the first place.

        • Caveman@lemmy.world
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          3 months ago
          • ax^2 + bx + c = 0
          • ax^2 + bx = -c move the c over
          • x^2 + (b/a)x = -c/a divide by a
          • x^2 + (b/a)x +(b/2a)^2 = -c/a + (b/2a)^2 complete the square
          • (x + b/2a)^2 = -c/a + (b/2a)^2 factor the left hand side
          • x + b/2a = sqrt(-c/a + (b/2a)^2) now we just tidy it up
          • x = -b/2a + sqrt(-c/a + b2/4a2)
          • x = -b/2a + (2a/2a) sqrt(-c/a + b2/4a2)
          • x = (-b + (2a)sqrt(-c/a + b2/4a2))/2a
          • x = (-b + sqrt(-4ac + b^2))/2a move 2a into the square root and multiply it with what’s inside

          The derivation of the quadratic formula is nice because it doesn’t rely on anything fancy and it’s all tricks the teacher is likely to teach around the same time you’re learning it. It’s not voodoo shit, it’s just the ax^2 + bx + c = 0 and you solve for x.

          • JWBananas@lemmy.world
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            3 months ago

            Thanks for the alternative explanation. Completing the square never made much sense to me either, so I never would have arrived there.