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Joined 9 months ago
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Cake day: January 1st, 2024

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  • You want to figure out distance per second. One way to do this is calculate distance apart at t=0,1,2…

    The difference between each point would be the average speed over that second.

    Using sqrt(b2+g2):

    t0 = 0 t1 = 1.554m
    s1 = (1.554m-0m)/1s = 1.554m/s t2 = 3.108m
    s2=(3.108m-1.554m)= 1.554m/s

    As you continue this you will see they travel at a constant speed apart from each other. The reason this is working is because you need to divide distance by time. Dividing by 1 second won’t change the value of the number after you subtract. If you notice you can do (t2-t0)/2s and also get the same answer.



  • It’s the difference of distances apart over time. Aka how fast bf is moving away from gf, aka what the question is asking for.

    Yes, if you want to be pedantic, velocity a vector with direction, so I guess you’d have to frame the question relative to either the boyfriend or girlfriend, but I don’t think the difference between speed and velocity is part of the question.